[Toán 8] Toán khó?

V

vithaobaby

N

nguyenbahiep1

Bài 2

$M = \frac{2(x+\sqrt{x}+1)}{\sqrt{x}} \\ \\ TXD: x > 0 , x\not = 1 \\ \\ M- 5 = \frac{2x-3\sqrt{x}+2}{\sqrt{x}} = \frac{2(\sqrt{x}-\frac{3}{4})^2 + \frac{7}{8}}{\sqrt{x}} > 0 \\ \\ \Rightarrow M > 5 \\ \\ M = \frac{2(x+\sqrt{x}+1)}{\sqrt{x}} > 0 \\ \\ M < 0 \Rightarrow vo -nghiem$
 
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