[Toán 8] Tìm GTNN

  • Thread starter kimanh1501.hy@gmail.com
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E

eye_smile

A=x2−2x+2014x2=20132014x2+12014(x2−4028x+20142)x2=20132014+(x−2014)22014x2≥20132014A=\dfrac{x^2-2x+2014}{x^2}=\dfrac{\dfrac{2013}{2014}x^2+\dfrac{1}{2014}(x^2-4028x+2014^2)}{x^2}=\dfrac{2013}{2014}+\dfrac{(x-2014)^2}{2014x^2} \ge \dfrac{2013}{2014}

Dấu = xảy ra \Leftrightarrow x=2014
 
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