[Toán 8] thu gọn bt sau

T

toiyeu9a3

$Bt = \dfrac{2x + 3y}{(y + 2)(x - 3)} - \dfrac{6 - xy}{(y + 2)(x+3)} - \dfrac{x^2 + 9}{(x - 3)(x +3)}$
$= \dfrac{(2x + 3y)(x + 3) - (6 - xy)(x - 3) - (x^2 + 9)(y + 2)}{(y + 2)(x - 3)(x + 3)}$
$= 0$
 
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