N
nhoclovestory


bài 1: giải phương trình
a) $\frac{x+2}{x+1}+\frac{3}{x-2}= \frac{3}{x^2-x-2}+1$
b) $\frac{x+6}{x-5}+\frac{x-5}{x+6}=\frac{2x^2+23x+61}{x^2+x-30}$
c) $\frac{6}{x-5}+\frac{x+2}{x-8}=\frac{18}{(x-5)(8-x)}-1$
d) $\frac{x-4}{x-1}+\frac{x+4}{x+1}=2$
e)$ \frac{3}{x+1}-\frac{1}{x-2}= \frac{9}{(x+1)(2-x)}$
bài 2: giải phương trình
a)$ \frac{x+1}{x^2+x+1}-\frac{x-1}{x^2-x+1}=\frac{3}{x(x^4+x^2+1)}$
b) $\frac{x+2}{x^2+2x+4}-\frac{x-2}{x^2-2x+4}=\frac{6}{x(x^2+4x^2+16)}$
c) $\frac{x^2-x}{x+3}-\frac{x^2}{x-3}=\frac{7x^2-3x}{9-x^2}$
a) $\frac{x+2}{x+1}+\frac{3}{x-2}= \frac{3}{x^2-x-2}+1$
b) $\frac{x+6}{x-5}+\frac{x-5}{x+6}=\frac{2x^2+23x+61}{x^2+x-30}$
c) $\frac{6}{x-5}+\frac{x+2}{x-8}=\frac{18}{(x-5)(8-x)}-1$
d) $\frac{x-4}{x-1}+\frac{x+4}{x+1}=2$
e)$ \frac{3}{x+1}-\frac{1}{x-2}= \frac{9}{(x+1)(2-x)}$
bài 2: giải phương trình
a)$ \frac{x+1}{x^2+x+1}-\frac{x-1}{x^2-x+1}=\frac{3}{x(x^4+x^2+1)}$
b) $\frac{x+2}{x^2+2x+4}-\frac{x-2}{x^2-2x+4}=\frac{6}{x(x^2+4x^2+16)}$
c) $\frac{x^2-x}{x+3}-\frac{x^2}{x-3}=\frac{7x^2-3x}{9-x^2}$
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