[Toán 7] Tìm min A

N

ngocbich74

$\dfrac{5-3x}{2x-1}$=$\dfrac{\dfrac{3}{2}-3x+\dfrac{7}{2}}{2x-1}$=$\dfrac{-3}{2}+\dfrac{\dfrac{7}{2}}{2x-1}$
Em tìm min của$\dfrac{\dfrac{7}{2}}{2x-1}$
\Rightarrow2x-1 <0
2x-1 phải lớn nhất
2x-1 thuộc Z
\Rightarrow2x-1=-1\Rightarrowx=0
\Rightarrowmin là -5
 
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