cm: A=1/1.3+1/3.5+...+1/(2n-1)(2n+1) <1/2
$A=\dfrac1{1.3}+\dfrac1{3.5}+\dots+\dfrac1{(2n-1)(2n+1)}
\\=\dfrac12 \left[\dfrac 2{1.3}+\dfrac 2{3.5}+\dots+\dfrac 2{(2n-1)(2n+1)} \right]
\\=\dfrac12 \left(1-\dfrac13+\dfrac13-\dfrac15+\dots+\dfrac1{2n-1}-\dfrac1{2n+1} \right)
\\=\dfrac12-\dfrac1{2(2n+1)}<\dfrac12$