H
hung.nguyengia2013@yahoo.com.vn


Giải bất phương trình:
\[\dfrac{{{{\log }_{3 + {x^2}}}{{\left( {{x^2} - 6} \right)}^2}}}{2} < 2 + \dfrac{{{{\log }_{\sqrt 2 }}\left( {\dfrac{1}{{64}}} \right)}}{{12}}\]
\[\dfrac{{{{\log }_{3 + {x^2}}}{{\left( {{x^2} - 6} \right)}^2}}}{2} < 2 + \dfrac{{{{\log }_{\sqrt 2 }}\left( {\dfrac{1}{{64}}} \right)}}{{12}}\]