[Toán 11] Tính giới hạn

N

nghgh_97

E

eye_smile

1.
picture.php


2. $\lim\limits_{x\to 2} \dfrac{\sqrt[3]{3x+2}-2}{x-2}=\lim\limits_{x\to 2} \dfrac{3x+2-8}{(x-2)(\sqrt[3]{3x+2}^2+4+2\sqrt[3]{3x+2})}=\lim\limits_{x\to 2} \dfrac{3}{\sqrt[3]{3x+2}^2+4+2\sqrt[3]{3x+2}}=\dfrac{1}{4}$
 
Last edited by a moderator:
Top Bottom