[Toán 11] Giới hạn

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niemkieuloveahbu

Ta có [tex] |\frac{cosx}{n}| \leq \frac{1}{n}[/tex]

Mà [TEX]lim\frac{1}{n} =0 \Rightarrow \lim\frac{cosx}{n}=0[/TEX]

[TEX]\lim_{x \to 0}\frac{1-cosx}{x^2}= \lim_{x \to 0} \frac{2sin^2\frac{x}{2}}{4(\frac{x}{2})^2}=\frac{1}{2}[/TEX]

[TEX]\lim_{x\to 0}\frac{sinx}{2x}=\frac{1}{2}\lim_{x \to 0} \frac{sinx}{x}=\frac{1}{2}[/TEX]
 
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