toan 10 ctlg

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nhockthongay_girlkute

cho tam giác ABC đặt BC=a, AC=b, AB=c
cmr: tan A/tan B=(a^2+c^2-b^2)/(b^2+c^2-a^2)
[TEX]tan A=\frac{sinA}{cosA}=\frac{\frac{a}{2R}}{\frac{b^2+c^2-a^2}{2bc}}=\frac{abc}{R(b^2+c^2-a^2)}[/TEX]
Tương tự [TEX]tan B =\frac{abc}{R(a^2+c^2-b^2)}[/TEX]
[TEX]\Rightarrow \frac{tan A}{tan B}=\frac{a^2+c^2-b^2}{b^2+c^2-a^2}[/TEX]
 
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