33. $n_{glucose} = \dfrac{2975}{180} = 16,527778 \ (mol)$
$C_6H_{12}O_6 \overset{men \ ruou}{\longrightarrow} 2C_2H_5OH + 2CO_2$
$n_{ethanol \ (ly \ thuyet)} = 2. 16,527778 = 33,055556 \ (mol)$
$n_{ethanol \ (thuc \ te)} = 33,055556 . \dfrac{80}{100} = 26,4444448 \ (mol)$
$m_{ethanol \ (thuc \ te)} = 26,4444448 . 46 = 1216,444461 \ (g)$
$m_{ruou \ 40 \ do} = 1216,444461 . \dfrac{100}{40} = 3041,111152 \ (g)$
$V_{ruou \ 40 \ do} = \dfrac{3041,111152}{0,8} = 3801,38894 \ (ml) \approx 3,8 \ (l)$