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yumi_26

Gọi a là số mol NO, b là số mol $NO_2$

$NO \ \ 30 \ \ \ \ \ \ \ \ \ \ \ \ \ 12,5$
$\ \ \ \ \ \ \ \searrow \ \ \ \ \nearrow$
$\ \ \ \ \ \ \ \ \ \ \ \ \ 16,75.2$
$\ \ \ \ \ \ \ \nearrow \ \ \ \ \searrow$
$NO_2 \ \ 46 \ \ \ \ \ \ \ \ \ \ \ \ \ 3,5$

\Rightarrow $\dfrac{a}{b} = \dfrac{12,5}{3,5} = \dfrac{25}{7}$ \Rightarrow $7a - 25b = 0 \ (1)$

$Al -> Al^{+3} + 3e$
$\dfrac{4,59}{27}$...........0,51

$N^{+5} + 3e -> NO$
..........3a.......a

$N^{+5} + e -> NO_2$
...........b............b

\Rightarrow $3a + b = 0,51 \ (2)$

(1),(2) \Rightarrow a = ...; b = ...
 
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