tính S

E

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C/m tg.BDH đ.dạng tg.ADC

\Rightarrow $\dfrac{DH}{DC}=\dfrac{BD}{AD}$

\Leftrightarrow $\dfrac{DH}{16}=\dfrac{8}{14+DH}$

\Rightarrow $HD=-7+\sqrt{177}$

\Rightarrow $S_{ABC}=...$
 
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