Tính pH ?

C

conlokmaudakam96

CH3COONa -----> CH3COO- + Na*
CM_CH3COO- = CM_CH3COOH = 0,1 M
CH3COO- + H2O <====> CH3COOH + OH-
gọi x là CM CH3COO- phân ly ra ion
ta có : [CH3COOH].[OH-]/ [CH3COO-] = 6,71.10^-10
<=> x.x/(0,1-x) = 5,71.10^-10 => x = 7,56.10^-6 M => pOH = 5 => pH = 9 ( vì pH + pOH = 14)
 
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