[TEX]A= (1-\frac{1}{2^2}).(1-\frac{1}{3^2})...(1-\frac{1}{25^2})[/TEX]
[TEX]A= (1-\frac{1}{2})(1+\frac{1}{2}).(1-\frac{1}{3}).(1+\frac{1}{3})...(1-\frac{1}{25}).(1+\frac{1}{25})[/TEX]
[TEX]A=\frac{1}{2}.\frac{3}{2}.\frac{2}{3}.\frac{4}{3}...\frac{24}{25}.\frac{26}{25}[/TEX]
[TEX]A=\frac{1}{2}.\frac{26}{25}=\frac{13}{25}[/TEX]
Vậy[TEX] A =\frac{13}{25}[/TEX]