1x2+2x3+3x4+....+49x50
=1x(1+1)+2x(2+1)+3x(3+1)+....49x(49+1)
=([TEX]1^2+2^2+3^2+.....+49^2[/TEX])+(1+2+3+....+49)
=[TEX]\frac{49x(49+1)x(2x49+1)}{6}+\frac{49x(49+1)}{2}[/TEX]
=[TEX]\frac{49x(49+1)x[(2x49+1)+3]}{6}[/TEX]
Rồi thế số vô là OK!
1x2+2x3+3x4+....+49x50
=1x(1+1)+2x(2+1)+3x(3+1)+....49x(49+1)
=([TEX]1^2+2^2+3^2+.....+49^2[/TEX])+(1+2+3+....+49)
=[TEX]\frac{49x(49+1)x(2x49+1)}{6}+\frac{49x(49+1)}{2}[/TEX]
=[TEX]\frac{49x(49+1)x[(2x49+1)+3]}{6}[/TEX]
Rồi thế số vô là OK!
1x2+2x3+3x4+....+49x50
=1x(1+1)+2x(2+1)+3x(3+1)+....49x(49+1)
=([TEX]1^2+2^2+3^2+.....+49^2[/TEX])+(1+2+3+....+49)
=[TEX]\frac{49x(49+1)x(2x49+1)}{6}+\frac{49x(49+1)}{2}[/TEX]
=[TEX]\frac{49x(49+1)x[(2x49+1)+3]}{6}[/TEX]
Rồi thế số vô là OK!
1x2+2x3+3x4+....+49x50
=1x(1+1)+2x(2+1)+3x(3+1)+....49x(49+1)
=([TEX]1^2+2^2+3^2+.....+49^2[/TEX])+(1+2+3+....+49)
=[TEX]\frac{49x(49+1)x(2x49+1)}{6}+\frac{49x(49+1)}{2}[/TEX]
=[TEX]\frac{49x(49+1)x[(2x49+1)+3]}{6}[/TEX]
Rồi thế số vô là OK!