Tính nhanh

H

hiensau99

1. [TEX]\frac{2.4 + 2.4.8 +4.8.16+8.16.32}{3.4+2.6.8+4.12.16+8.24.32}=\frac{2.4(1+8+4.16+16.32)}{3.4(1+8+4.16+8.2.32)}=\frac{2}{3}[/TEX]

2. Đề bài
:|

3/. Đặt: B=1*10+2*9+3*8+...+8*3+9*2+10*1

= 2.( 1.10+2.9+3.8+4.7+5.6)

+ A = 1+ 3+ 6 + 10 +..+45 +55
\Rightarrow
A= 1+ (1+2) + (1+2+3) + (1+2+3+4) +..+ (1+2+..+10)
\Rightarrow
A = 1.10+2.9+3.8+4.7+5.6
\Rightarrow
A= [TEX]\frac{1}{2}[/TEX].B
Vậy:
[TEX]\frac{1+3+6+10+...+45+55}{1*10+2*9+3*8+...+8*3+9*2+10*1}=\frac{1}{2}[/TEX]
 
P

pvsme2510

1. [TEX]\frac{2.4 + 2.4.8 +4.8.16+8.16.32}{3.4+2.6.8+4.12.16+8.24.32}=\frac{2.4(1+8+4.16+16.32)}{3.4(1+8+4.16+8.2.32)}=\frac{2}{3}[/TEX]

2. Đề bài
:|

3/. Đặt: B=1*10+2*9+3*8+...+8*3+9*2+10*1

= 2.( 1.10+2.9+3.8+4.7+5.6)

+ A = 1+ 3+ 6 + 10 +..+45 +55
\Rightarrow
A= 1+ (1+2) + (1+2+3) + (1+2+3+4) +..+ (1+2+..+10)
\Rightarrow
A = 1.10+2.9+3.8+4.7+5.6
\Rightarrow
A= [TEX]\frac{1}{2}[/TEX].B
Vậy:
[TEX]\frac{1+3+6+10+...+45+55}{1*10+2*9+3*8+...+8*3+9*2+10*1}=\frac{1}{2}[/TEX]
 
P

pvsme2510

1. [TEX]\frac{2.4 + 2.4.8 +4.8.16+8.16.32}{3.4+2.6.8+4.12.16+8.24.32}=\frac{2.4(1+8+4.16+16.32)}{3.4(1+8+4.16+8.2.32)}=\frac{2}{3}[/TEX]

2. Đề bài
:|

3/. Đặt: B=1*10+2*9+3*8+...+8*3+9*2+10*1

= 2.( 1.10+2.9+3.8+4.7+5.6)

+ A = 1+ 3+ 6 + 10 +..+45 +55
\Rightarrow
A= 1+ (1+2) + (1+2+3) + (1+2+3+4) +..+ (1+2+..+10)
\Rightarrow
A = 1.10+2.9+3.8+4.7+5.6
\Rightarrow
A= [TEX]\frac{1}{2}[/TEX].B
Vậy:
[TEX]\frac{1+3+6+10+...+45+55}{1*10+2*9+3*8+...+8*3+9*2+10*1}=\frac{1}{2}[/TEX]
 
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