Ta có:[tex]A=\frac{\sqrt{ab}}{c}-\frac{\sqrt{bc}}{a}-\frac{\sqrt{ca}}{b}=\sqrt{abc}(\frac{1}{c\sqrt{c}}-\frac{1}{b\sqrt{b}}-\frac{1}{a\sqrt{a}})[/tex]
Đặt [tex]x=\frac{1}{\sqrt{c}},y=-\frac{1}{\sqrt{b}},z=-\frac{1}{\sqrt{a}}\Rightarrow x+y+z=0\Rightarrow x^3+y^3+z^3=3xyz\Rightarrow \frac{1}{c\sqrt{c}}-\frac{1}{b\sqrt{b}}-\frac{1}{a\sqrt{a}}=3.\frac{1}{\sqrt{abc}}\Rightarrow A=3[/tex]