Tính chát chia hết

I

icy_tears

Ta có:
x20161x^{2016} - 1
=(x10081)(x1008+1)= (x^{1008} - 1)(x^{1008} + 1)
=(x61).q(x).(x1008+1)= (x^6 - 1) . q(x) . (x^{1008} + 1)
=(x+1)(x1)(x4+x2+1).q(x).(x1008+1)= (x + 1)(x - 1)(x^4 + x^2 + 1) . q(x) . (x^{1008} + 1)
=(x5x4+x3x2+x1)(x+1).q(x).(x1008+1)= (x^5 - x^4 + x^3 - x^2 + x - 1)(x + 1) . q(x) . (x^{1008} + 1)
\Rightarrow ĐPCM
 
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