Xin lỗi nhé, tớ tính như thế này:
Ta có :20122011+20132012+20142013 =1−20121+1−20131+1−20141 =3−(20121+20131+20141)
Thay x=2012, ta có: =3−(x1+x+11+x+21) =3−x(x+1)(x+2)x(x+1)+x(x+2)+(x+1)(x+2) =3−x3+3.x2+2x3.x2+x.6+2 =x3+3.x2+2x3.x3+6.x2−2 =8144865728+12144432+402424434579184+24288864+2 =815701418424458868050 =407850709212229434025