c.rắn thu được gồm CuO và Cu dư
m c.rắn tăng [tex]\fn_jvn \frac{1}{6}m_{Cu}\Rightarrow n_{O_{2}}=\frac{1}{192}m_{Cu}(mol)[/tex]
[tex]\fn_jvn 2Cu+O_{2}\overset{t^{0}}{\rightarrow}2CuO[/tex]
[tex]\fn_jvn \Rightarrow n_{CuO}=2.\frac{1}{192}m_{Cu}=\frac{1}{96}m_{Cu}[/tex]
[tex]\fn_jvn \Rightarrow m_{CuO}=\frac{1}{96}m_{Cu}.80=\frac{5}{6}m_{Cu}[/tex]
[tex]\fn_jvn n_{Cu}(dư)=\frac{m_{Cu}}{64}-2.\frac{1}{192}m_{Cu}=\frac{1}{192}m_{Cu}[/tex]
[tex]\fn_jvn \Rightarrow m_{Cu} (dư)=\frac{1}{192}.m_{Cu}.64=\frac{1}{3}.mCu[/tex]
vậy
![upload_2017-9-28_7-2-51.png upload_2017-9-28_7-2-51.png](https://s3.icankid.io/hmo-forum/data/attachments/22/22571-85e83d0868015e1494050734365814ef.jpg)