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Học sinh chăm học
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20 Tháng chín 2017
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Vĩnh Phúc
Ta có: 34=2(x1)(x3)+5(x3)(x8)+12(x8)(x20)1x20=(x1)(x3)(x1)(x3)+(x3)(x8)(x3)(x8)+(x8)(x12)(x8)(x12)1x20=1x31x1+1x81x3+1x201x81x20=1x134=1x13(x1)=43x+3=4x=13\frac{-3}{4}= \frac{2}{(x-1)(x-3)}+\frac{5}{(x-3)(x-8)}+\frac{12}{(x-8)(x-20)}-\frac{1}{x-20}=\frac{(x-1)-(x-3)}{(x-1)(x-3)}+\frac{(x-3)-(x-8)}{(x-3)(x-8)}+\frac{(x-8)-(x-12)}{(x-8)(x-12)}-\frac{1}{x-20} =\frac{1}{x-3}-\frac{1}{x-1}+\frac{1}{x-8}-\frac{1}{x-3}+\frac{1}{x-20}-\frac{1}{x-8}-\frac{1}{x-20} =\frac{1}{x-1} \Leftrightarrow \frac{-3}{4}=\frac{1}{x-1}\Rightarrow -3(x-1)=4\Leftrightarrow -3x+3=4\Leftrightarrow x=-\frac{1}{3}
Vây: x=13x=-\frac{1}{3}
 
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