[tex]5^{x}.5^{x+1}.5^{x+2} \leq 100...0 (18 chữ số 0)\Leftrightarrow 5^{3x+3}\leq 10^{18}\Leftrightarrow 5^{3x+3-18}\leq 2^{18}=4^9< 5^9\Rightarrow 3x-15< 9\Rightarrow 3x< 24\Rightarrow x< 8\Rightarrow x\leq 7[/tex]
Ta thấy: Với x = 7 thì [tex]5^{3x+3-18}=5^6< 8^6=(2^3)^6=2^{18}[/tex]
Vậy [tex]x\leq 7[/tex]