[TEX]n_{H_2}=\frac{V_{H_2}}{22,4}(dktc)=\frac{8,96}{22,4}=0,4(mol)[/TEX]
PTPƯ:
[TEX]Zn+2HCl \to ZnCl_2+H_2[/TEX]
(mol) 1--2--1--1
(mol) _--?--_--0,4
[TEX]\Rightarrow n_{HCl}=\frac{0,4.2}{1}=0,8(mol)[/TEX]
Ta có: [TEX]C_{M_{ddHCl}}=\frac{n_{HCl}}{V_{ddHCl}}[/TEX]
[TEX]\Rightarrow 1=\frac{0,8}{V_{ddHCl}}[/TEX]
[TEX]\Rightarrow V_{ddHCl}=0,8^l[/TEX]