Tìm Min

C

chaizo1234567

Bài làm

Ta có:
$A=\frac{c^2}{a^2+b^2}+\frac{4c^2}{2ab}+\frac{c^2}{ab}+\frac{ab+c^2}{c^2}$
Do a+b\leqc
\Rightarrow$c^2$\geq$a^2+b^2+2ab$
\RightarrowA\geq$\frac{(c+2c+c)^2}{a^2+b^2+3ab}$+$\frac{a^2+b^2+3ab}{c^2}$
\RightarrowA\geq8.................
 
Last edited by a moderator:
Top Bottom