L
linh_su_2k


tìm A max, B min của
B max=4.|y-1|+(x^2-1)^2+13
A min=(x^2-4)^2+(x+2)-13
a max=5-(x^2+1)^2
=13_(x+2)^2-|y+1|
= |x+7|+|x+1|
B max=4.|y-1|+(x^2-1)^2+13
A min=(x^2-4)^2+(x+2)-13
a max=5-(x^2+1)^2
=13_(x+2)^2-|y+1|
= |x+7|+|x+1|