[laTEX]M = 4(x+\frac{3}{2})^2 + 6 \geq 6 \\ \\ Min M = 6 \\ \\ x = - \frac{3}{2}[/laTEX]
[latex]N = (x+\frac{1}{2})^2 + \frac{3}{4} \geq \frac{3}{4} \\ \\ Min M = \frac{3}{4} \\ \\ x = - \frac{1}{2}[/laTEX]
Bài 2
[laTEX]E = \frac{97}{12}-3(x+\frac{7}{6})^2 \leq \frac{97}{12} \\ \\ Max E = \frac{97}{12} \\ \\ x = - \frac{7}{6} \\ \\ F = -\frac{3}{4}-(x-\frac{1}{2})^2 \leq \frac{-3}{4} \\ \\ Max E = \frac{-3}{4} \\ \\ x = \frac{1}{2}[/laTEX]