Tich phan

C

conga222222

Tinh tich phan cua
(x - 3)/(3 can(x +1) + x +3)
can tu 1 den 3

\[\begin{array}{l}
\frac{{x - 3}}{{3\sqrt {x + 1} + x + 3}} = \frac{{\left( {x - 3} \right)\left( {3\sqrt {x + 1} - x - 3} \right)}}{{9x + 9 - {x^2} - 6x - 9}} = \frac{{x + 3 - 3\sqrt {x + 1} }}{x}\\
\to \int_1^3 {\frac{{x - 3}}{{3\sqrt {x + 1} + x + 3}}dx} = \int_1^3 {\frac{{x + 3 - 3\sqrt {x + 1} }}{x}dx} = ...
\end{array}\]
 
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