B
bedieu_96


cho :a+b+c=2004
[TEX]{\frac{1}{a+b}+{\frac{1}{b+c}+{\frac{1}{c+a}[/TEX]
Tính M=[TEX]{\frac{a}{b+c}+{\frac{b}{c+a}+{\frac{c}{a+b}[/TEX]
[TEX]{\frac{1}{a+b}+{\frac{1}{b+c}+{\frac{1}{c+a}[/TEX]
Tính M=[TEX]{\frac{a}{b+c}+{\frac{b}{c+a}+{\frac{c}{a+b}[/TEX]
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