[tex]<=>2sin2x.cos2x.sinx+\sqrt{3}cosx.sin4x=2\sqrt{2}sin(\frac{\pi}{3}+x)<=>sin4x.sinx+\sqrt{3}cosx.sin4x=2\sqrt{2}sin(\frac{\pi}{3}+x)<=>sin4x.(\frac{1}{2}sinx+\frac{\sqrt{3}}{2}cosx)=\sqrt{2}sin(\frac{\pi}{3}+x)<=>sin4x.sin(x+\frac{\pi}{3})=\sqrt{2}sin(x+\frac{\pi}{3})<=>sin(x+\frac{\pi}{3})=sin(x+\frac{\pi}{3})[/tex]