Toán 6 So sánh

Nguyễn Linh_2006

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so sánh 10^2020+1/10^2021+1 và 10^2020-11/10^2021-10
Đặt [tex]A=\frac{10^{2020}+1}{10^{2021}+1}[/tex]

[tex]\rightarrow A-1=\frac{10^{2020}+1}{10^{2021}+1}-1=\frac{10^{2020}-10^{2021}}{10^{2021}+1}[/tex]

[tex]B=\frac{10^{2020}-10}{10^{2021}-10}[/tex]

[tex]\rightarrow B-1=\frac{10^{2020}-10}{10^{2021}-10}-1=\frac{10^{2020}-10^{2021}}{10^{2021}-10 }[/tex]

Có [tex]2020<2021\rightarrow 10^{2020}<10^{2021}\rightarrow 10^{2020}-10^{2021}<0[/tex]

[tex]10^{2021}+1>10^{2020}-10[/tex]

[tex]\Rightarrow \frac{10^{2020}-10^{2021}}{10^{2021}+1}>\frac{10^{2020}-10^{2021}}{10^{2021}-10}[/tex]

hay [tex]A-1>B-1\Rightarrow A>B[/tex]

hay [tex]\frac{10^{2020}+1}{10^{2021}+1}>\frac{10^{2020}-10}{10^{2021}-10}>\frac{10^{2020}-11}{10^{2021}-10}[/tex]

Vậy [tex]\frac{10^{2020}+1}{10^{2021}+1}>\frac{10^{2020}-11}{10^{2021}-10}[/tex]
 
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