[tex]\frac{\sqrt{2}}{\sqrt{3}+\sqrt{2}}+2\sqrt{3+\sqrt{2}-\sqrt{3}-\sqrt{6}}\\ =\sqrt{2}(\sqrt{3}-\sqrt{2})+\sqrt{2}.\sqrt{2(3+\sqrt{2}-\sqrt{3}-\sqrt{6})}\\ =\sqrt{6}-2+\sqrt{2}.\sqrt{6+2\sqrt{2}-2\sqrt{3}-2\sqrt{6}}\\ =\sqrt{6}-2+\sqrt{2}.(1+\sqrt{2}-\sqrt{3})\\ =\sqrt{6}-2+\sqrt{2}+2-\sqrt{6}=\sqrt{2}[/tex]