B
baby_dt


giúp mình câu này nhé
[TEX]2^{cos(\frac{2011.\pi}{4}-x)}=tanx[/TEX]
[TEX]9^x = 5^x + 4^x + 2sqrt{20}^x[/TEX]
[TEX]2^{cos(\frac{2011.\pi}{4}-x)}=tanx[/TEX]
[TEX]9^x = 5^x + 4^x + 2sqrt{20}^x[/TEX]
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