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[Tex] (1+cosx)^{log}_{cosx}sinx = (1+sinx)^ {log}_{sinx}cosx [/Tex]
[TEX] e^sinx = 1+ {log}_{e}(1+sinx) [/TEX]
sin2x - cosx= 1+ {log}_{2}sinx
[TEX] e^sinx = 1+ {log}_{e}(1+sinx) [/TEX]
sin2x - cosx= 1+ {log}_{2}sinx