[tex]PT\Leftrightarrow cos2(x+\frac{\pi}{3})+4cos(\frac{\pi}{2}-x-\frac{\pi}{3})=\frac{5}{2}\\\Leftrightarrow 1-2sin^2(x+\frac{\pi}{3})+4sin(x+\frac{\pi}{3})=\frac{5}{2}\\\Leftrightarrow 2sin^2(x+\frac{\pi}{3})-4sin(x+\frac{\pi}{3})+\frac{3}{2}=0\\\Leftrightarrow \left[\begin{array}{l} sin(x+\frac{\pi}{3})=\frac{3}{2}(L)\\sin(x+\frac{\pi}{3})=\frac{1}{2} \end{array}\right.[/tex]
Đơn giản rồi, bạn làm nốt nhé

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