Ta có:[tex](\frac{x}{x+1})^2+(\frac{x}{x-1})^2=90\Leftrightarrow (\frac{x}{x+1})^2+(\frac{x}{x-1})^2+2.(\frac{x}{x-1})(\frac{x}{x+1})=90+2.(\frac{x}{x-1})(\frac{x}{x+1})\Leftrightarrow (\frac{x}{x+1}+\frac{x}{x-1})^2=90+\frac{2x^2}{x^2-1}\Leftrightarrow (\frac{2x^2}{x^2-1})^2=90+\frac{2x^2}{x-1}[/tex]
Đặt [tex]t=\frac{2x^2}{x-1}\Rightarrow t^2=90+t\Leftrightarrow t^2-t-90=0[/tex]