phân tích đa thức thành nhân tử

M

maidoany_nhi

b.
2x4−x3+2x2+1
=2x4−2x3+x3+2x2+x2−x2+x−x+1
=(2x4+x3+x2)−(2x3+x2+x)+(2x2+x+1)
=x2(2x2+x+1)−x(2x2+x+1)+(2x2+x+1)
=(x2−x+1)(2x2+x+1)
d.
a5+ab4+b5
=a5−a2b3+a2b3+a3b2−a3b2+a4b−a4b+ab4+b5
=(b5−a2b3+a3b2)+(ab4−a3b2+a4b)+(a2b3−a4b+a5)
=b2(b3−a2b+a3)+ab(b3−a2b+a3)+a2(b3−a2b+a3)
=(b2+ab+a2)(b3−a2b+a3)
 
T

thoavnn

2x4−x3+2x2+1
=2x4−2x3+x3+2x2+x2−x2+x−x+1
=(2x4+x3+x2)−(2x3+x2+x)+(2x2+x+1)
=x2(2x2+x+1)−x(2x2+x+1)+(2x2+x+1)
=(x2−x+1)(2x2+x+1)
 
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