a)
Có H = N + G
[tex]\Rightarrow[/tex] N = H - G = 3000
[tex]\Rightarrow[/tex] L = [tex]\frac{N}{2}. 3,4 [/tex][tex]A^{O}[/tex] = 5100[tex]A^{O}[/tex]
G = X = 900
A = T = [tex]\frac{N}{2}[/tex] - G = 600
b)
Xét mạch 1:
[tex]A_{1}[/tex] = [tex]2T_{1}[/tex] = [tex]3G_{1}[/tex] = [tex]4X_{1}[/tex]
Có:
[tex]A_{1}[/tex]+[tex]T_{1}[/tex]+[tex]G_{1}[/tex]+[tex]X_{1}[/tex]=[tex]\frac{N}{2}[/tex]
[tex]\Rightarrow[/tex] [tex]A_{1}[/tex] = 720; [tex]T_{1}[/tex] = 360; [tex]G_{1}[/tex] = 240; [tex]X_{1}[/tex]= 180
[tex]\Rightarrow[/tex] %[tex]A_{1}[/tex] = 48%; %[tex]T_{1}[/tex] = 24%; %[tex]G_{1}[/tex] = 16%; %[tex]X_{1}[/tex] = 12%