ôn tập

L

levietdung1998

\[\begin{array}{l}
\left. \begin{array}{l}
\frac{1}{2}{n_{HCl}} = {n_{FeC{l_2}}} = 0,015 \to {n_{Fe}} = 0,015\\
{n_{{H_2}S{O_4}}} = {n_{FeS{O_4}}} = 0,05 \to {n_{Fe}} = 0,05
\end{array} \right\}\sum {_{Fe}} = 0,065\\
\\
+ {n_{Fe}} = \frac{{7,86}}{{56}} = 0,14\\
\to Fe\left( {du} \right) \to {n_{{H_2}}} = \frac{1}{2}{n_{HCl}} + {n_{{H_2}S{O_4}}} = 0,065 \to V = 1,456\left( l \right)
\end{array}\]
 
Last edited by a moderator:
You must log in or register to reply here.
Top Bottom