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phuong_dt94


[TEX]\left\{\begin{array}{!} (x^2+y^2)(1+1/xy)^2}=9\\(x^3+y^3)(1+1/xy)^3=27\end{array}\right.[/TEX]
[TEX]\left{\begin{array}{!}2x^2+4xy-2x-y+2=0\\3x^2+6xy-x+3y=0\end{aray}\right.[/TEX]
e cảm ơn nhiều ak!
[TEX]\left{\begin{array}{!}2x^2+4xy-2x-y+2=0\\3x^2+6xy-x+3y=0\end{aray}\right.[/TEX]
e cảm ơn nhiều ak!
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