tim so hang lon nhat trong khai trien
(1/3 + 2/3x)^10
[TEX]T_k =C_{10}^{k-1}(\frac{1}{3})^{11-k}(\frac{2}{3x})^{k-1}[/TEX]
\Rightarrow[TEX]a_{k-1} =C_{10}^{k-1}(\frac{1}{3})^{11-k}(\frac{2}{3})^{k-1}[/TEX]
[TEX]T_{k+1} =C_{10}^k(\frac{1}{3})^{10-k}(\frac{2}{3x})^k[/TEX]
\Rightarrow[TEX]a_k=C_{10}^k(\frac{1}{3})^{10-k}(\frac{2}{3})^k[/TEX]
[TEX]T_{k+2} =C_{10}^{k+1}(\frac{1}{3})^{9-k}(\frac{2}{3x})^{k+1}[/TEX]
\Rightarrow[TEX]a_{k+1} =C_{10}^{k+1}(\frac{1}{3})^{9-k}(\frac{2}{3})^{k+1}[/TEX]
[TEX]a_k max[/TEX]\Leftrightarrow[TEX]\left{a_k >= a_{k-1} \\ a_k >=a_{k+1}\\1<= k\inN<=9[/TEX]
giải ....