[tex]1-sin^2a-sin^2b+2sina.sinb.cos(a-b)=1-sin^2a-sin^2b+2sina.sinb.cosa.cosb+2sin^2a.sin^2b=cos^2a-sin^2b(1-2sin^2a)+\frac{sin2a.sin2b}{2}=\frac{1+cos2a}{2}-\frac{1-cos2b}{2}.cos2a+\frac{sin2a.sin2b}{2}=\frac{1}{2}+\frac{1}{2}(sin2a.sin2b+cos2a.cos2b)=\frac{1}{2}+\frac{1}{2}cos(2b-2a))[/tex]