[laTEX]dk: x > 0 \\ \\ log_7x = t \Leftrightarrow x = 7^t \\ \\ log_2(1+7^{\frac{t}{3}} ) = t \\ \\ 1+7^{\frac{t}{3}} = 2^t = 8^{\frac{t}{3}} \\ \\ (\frac{1}{8})^{\frac{t}{3}} + (\frac{7}{8})^{\frac{t}{3}} = 1 \\ \\ VT : nghich-bien \Rightarrow \frac{t}{3} = 1 \Rightarrow t = 3 \\ \\ x = 7^3 = 343[/laTEX]