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L

linh110

${\sin ^3}x({\mathop{\rm s}\nolimits} i{\rm{nx}} + \cos x) + c{\rm{o}}{{\rm{s}}^3}(\cos x - {\mathop{\rm s}\nolimits} {\rm{inx}}) = 3/4$

<=> [tex] \frac{1}{4} -2 sin^2 xcos^2 x -sinxcosxcos 2x=0 \\\\\\\\\\\\\\\\\\\\Leftrightarrow \frac{1}{4} -\frac{sin^2(2x)}{2} -\frac{sin 4x}{4} =0 \\\\\\\\\\\\\\\\\\\\\\\Leftrightarrow 1-(1-cos 4x) - sin 4x=0 [/tex]
 
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