khó nhe răng

N

no.one

[TEX]sinx^{14} + cosx^{13} =1[/TEX]
Ta có

[TEX]\left{\begin{sinx^{14}\leq sinx^2}\\{cosx^{13}\leq cosx^2}\\{sin^2x+cosx^2=1} [/TEX]

VT\leq1 dấu"=" \Leftrightarrow[TEX]\left{\begin{sinx^{14}=sinx^2}\\{cosx^{13}=cos^2x} [/TEX]

\Leftrightarrow[TEX]\left{\begin{sinx=0, sinx=1, sinx=-1}\\{cosx=0, cosx=1} [/TEX]
 
Top Bottom