hóa

E

endinovodich12

T

thupham22011998

Ta có: n$H_2S$=8,96/22,4=0,4 mol
\Rightarrow n $SO_2$=0,4 mol
Ta có: n NaOH=$\frac{80.1,28.25}{100.40}$=0,64 mol
vì $\frac{ n NaOH}{n SO_2}$>1

\Rightarrow Tạo ra 2 muối
 
You must log in or register to reply here.
Top Bottom