Al + 4HNO3 => Al(NO3)3 + NO + 2H2O
2x........................................2x
8 Al + 30HNO3 => 8Al(NO3)3 + 3N2O +15 H2O
8/3x..................................................x
10Al + 36HNO3 => 10Al(NO3)3 + 3N2 + 18H2O
10/3x..............................................x
=>(2x+8/3x+10/3x)27=10,8
=>x=0,05 mol
VNO=2.0,05.22,4=2.24 l
VN20=0,05.22,4=1,12l
VN2=0,05.22,4=1,12l