hoá học 8

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phuongthao.24

C

chaugiang81


$Fe + H_2SO_4 --> FeSO_4 + H_2$
$nH_2= 0.05 mol$
$=>nFe= 0.05 mol$ (theo pt)
$=>mFe= 2.8 g$
$=>mCu= 15- 2.8= 12.2 g$
 
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