Hóa học 8: Dung dịch

T

thupham22011998

$Zn+2HCl-->ZnCl_2+H_2$

Ta có: $n Zn=0,1 mol$

Theo pthh, ta có: $n H_2=n ZnCl_2=0,1 mol ; n HCl=0,2 mol$

$-->V HCl=0,2/2=0,1 l$

$-->V H_2=2,24 l$

$-->m ZnCl_2=0,1.136=13,6 g$
 
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