MgCO3 ------> MgO + CO2
CaCO3 ------> CaO + CO2
BaCO3 _-----> BaO + CO2
CO2 + Ca(OH)2 ---> CaCO3 + H2O(1)
CO2 + CaCO3 + H2O ----> Ca(HCO3)2(2)
Ca(HCO3)2 ---> CaCO3 + CO2 + H2O (3)
=> nCO2(1.2)= 10/100=0.1 mol
n CaCO3(3) = 6/100=0.06 mol
=> n CO2 (2) = 0.06=0.06mol
=> n CO2(1) = N CaCO3(1)= 0.06+0.1 = 0.16 mol
=> Tổng n CO2 = 0.16+ 0.06=0.22 mol
=> x+y+z = 0,22 => y+z = 0,22-x(1)
Mặt khác ta có:
84x+100y+197z=20
100y+197z= 20-84x(2)
nhân (1)*100.
=>(1) - (2): -97z=2-16x hay 97z = 16x-2
Nhân (1)* 197.
=>(1)-(2): 97y=23,34-113x
Vì z,y>0 nên:
x>0,125; x<0,206
=> mMgCO3 (10,5;17,304)
=>%mMgCO3=(52,5;86,52)